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Câu hỏi: Cho hàm số $f\left( x \right)=\dfrac{1}{{{\left( 3x-2 \right)}^{3}}}$. Mệnh đề nào sau đây đúng?
A. $\int{f\left( x \right)} \text{d}x=\dfrac{1}{6{{\left( 3x-2 \right)}^{2}}}+C$.
B. $\int{f\left( x \right)} \text{d}x=-\dfrac{1}{6{{\left( 3x-2 \right)}^{2}}}+C$.
C. $\int{f\left( x \right)} \text{d}x=-\dfrac{1}{3{{\left( 3x-2 \right)}^{2}}}+C$.
D. $\int{f\left( x \right)} \text{d}x=\dfrac{1}{3{{\left( 3x-2 \right)}^{2}}}+C$.
A. $\int{f\left( x \right)} \text{d}x=\dfrac{1}{6{{\left( 3x-2 \right)}^{2}}}+C$.
B. $\int{f\left( x \right)} \text{d}x=-\dfrac{1}{6{{\left( 3x-2 \right)}^{2}}}+C$.
C. $\int{f\left( x \right)} \text{d}x=-\dfrac{1}{3{{\left( 3x-2 \right)}^{2}}}+C$.
D. $\int{f\left( x \right)} \text{d}x=\dfrac{1}{3{{\left( 3x-2 \right)}^{2}}}+C$.
Ta có: $\int{f\left( x \right)} \text{d}x=\int{\dfrac{1}{{{\left( 3x-2 \right)}^{3}}}\text{d}x}=\dfrac{1}{3}\int{\dfrac{1}{{{\left( 3x-2 \right)}^{3}}}\text{d}\left( 3x-2 \right)}=-\dfrac{1}{6{{\left( 3x-2 \right)}^{2}}}+C$.
Đáp án B.