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Câu hỏi: Cho hàm số $f\left( x \right)=4{{x}^{3}}+\dfrac{1}{x}, \left( x\ne 0 \right)$. Trong các khẳng định sau, khẳng định nào đúng?
A. $\int{f\left( x \right)\text{d}x}={{x}^{4}}-\ln \left| x \right|+C$.
B. $\int{f\left( x \right)\text{d}x}={{x}^{3}}+\ln \left| x \right|+C$.
C. $\int{f\left( x \right)\text{d}x}={{x}^{4}}+\ln \left| x \right|+C$.
D. $\int{f\left( x \right)\text{d}x}={{x}^{4}}-\dfrac{1}{{{x}^{2}}}+C$.
A. $\int{f\left( x \right)\text{d}x}={{x}^{4}}-\ln \left| x \right|+C$.
B. $\int{f\left( x \right)\text{d}x}={{x}^{3}}+\ln \left| x \right|+C$.
C. $\int{f\left( x \right)\text{d}x}={{x}^{4}}+\ln \left| x \right|+C$.
D. $\int{f\left( x \right)\text{d}x}={{x}^{4}}-\dfrac{1}{{{x}^{2}}}+C$.
Ta có $\int{f\left( x \right)\text{d}x}=\int{\left( 4{{x}^{3}}+\dfrac{1}{x} \right)\text{d}x}={{x}^{4}}+\ln \left| x \right|+C$.
Đáp án C.