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Câu hỏi: Cho biết $\int{f\left( x \right)}\text{d}x=4{{x}^{3}}-3{{x}^{2}}+2x+C$. Hàm số $f\left( x \right)$ là
A. $f\left( x \right)={{x}^{4}}-{{x}^{3}}+{{x}^{2}}$.
B. $f\left( x \right)={{x}^{3}}-{{x}^{2}}+2x+1$.
C. $f\left( x \right)={{x}^{4}}-{{x}^{3}}+{{x}^{2}}+3x$.
D. $f\left( x \right)=12{{x}^{2}}-6x+2$.
A. $f\left( x \right)={{x}^{4}}-{{x}^{3}}+{{x}^{2}}$.
B. $f\left( x \right)={{x}^{3}}-{{x}^{2}}+2x+1$.
C. $f\left( x \right)={{x}^{4}}-{{x}^{3}}+{{x}^{2}}+3x$.
D. $f\left( x \right)=12{{x}^{2}}-6x+2$.
Ta có $\int{f\left( x \right)}\text{d}x=4{{x}^{3}}-3{{x}^{2}}+2x+C$ $\Rightarrow f\left( x \right)=12{{x}^{2}}-6x+2$.
Đáp án D.