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Câu hỏi: Cho $a>0$ và $a\ne 1$, khi đó ${{\log }_{{{a}^{2}}}}\sqrt[4]{{{a}^{3}}}$ bằng
A. $-\dfrac{3}{8}$.
B. $\dfrac{3}{4}$.
C. $\dfrac{3}{8}$.
D. $\dfrac{3}{2}$.
A. $-\dfrac{3}{8}$.
B. $\dfrac{3}{4}$.
C. $\dfrac{3}{8}$.
D. $\dfrac{3}{2}$.
Ta có ${{\log }_{{{a}^{2}}}}\sqrt[4]{{{a}^{3}}}=\dfrac{1}{2}.{{\log }_{a}}{{a}^{\dfrac{3}{4}}}=\dfrac{1}{2}.\dfrac{3}{4}.{{\log }_{a}}a=\dfrac{3}{8}$.
Đáp án C.