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Câu hỏi: Biết $\int\limits_{-1}^{1}{f\left( x \right)\text{d}x}=6$, tích phân $\int\limits_{0}^{1}{f\left( 2x-1 \right)\text{d}x}$ bằng
A. 3.
B. 6.
C. 12.
D. 2.
A. 3.
B. 6.
C. 12.
D. 2.
Ta có $\int\limits_{0}^{1}{f\left( 2x-1 \right)\text{d}x}=\dfrac{1}{2}\int\limits_{0}^{1}{f\left( 2x-1 \right)\text{d}\left( 2x-1 \right)}=\dfrac{1}{2}\int\limits_{-1}^{1}{f\left( t \right)\text{d}t}=\dfrac{1}{2}.6=3$.
Đáp án A.