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Câu hỏi: Trong không gian $Oxyz$, cho ba điểm $A\left( 3;0;0 \right)$, $B\left( 0;1;0 \right)$ và $C\left( 0;0;-2 \right)$. Mặt phẳng $\left( ABC \right)$ có phương trình là:
A. $\dfrac{x}{3}+\dfrac{y}{-1}+\dfrac{z}{2}=1$.
B. $\dfrac{x}{3}+\dfrac{y}{1}+\dfrac{z}{-2}=1$.
C. $\dfrac{x}{3}+\dfrac{y}{1}+\dfrac{z}{2}=1$.
D. $\dfrac{x}{-3}+\dfrac{y}{1}+\dfrac{z}{2}=1$.
A. $\dfrac{x}{3}+\dfrac{y}{-1}+\dfrac{z}{2}=1$.
B. $\dfrac{x}{3}+\dfrac{y}{1}+\dfrac{z}{-2}=1$.
C. $\dfrac{x}{3}+\dfrac{y}{1}+\dfrac{z}{2}=1$.
D. $\dfrac{x}{-3}+\dfrac{y}{1}+\dfrac{z}{2}=1$.
$\left( ABC \right):\dfrac{x}{a}+\dfrac{y}{b}+\dfrac{z}{c}=1$ hay $\left( ABC \right):\dfrac{x}{3}+\dfrac{y}{1}+\dfrac{z}{-2}=1$.
Đáp án B.