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Câu hỏi: Tìm nguyên hàm của hàm số $f(x)=3{{x}^{2}}+8\sin x$.
A. $\int{f\left(x \right)\text{d}x}=6x-8\cos x+C$.
B. $\int{f\left(x \right)\text{d}x}=6x+8\cos x+C$.
C. ${\int{f\left(x \right)\text{d}x}={{x}^{3}}-8\cos x+C}$.
D. $\int{f\left(x \right)\text{d}x}={{x}^{3}}+8\cos x+C$.
A. $\int{f\left(x \right)\text{d}x}=6x-8\cos x+C$.
B. $\int{f\left(x \right)\text{d}x}=6x+8\cos x+C$.
C. ${\int{f\left(x \right)\text{d}x}={{x}^{3}}-8\cos x+C}$.
D. $\int{f\left(x \right)\text{d}x}={{x}^{3}}+8\cos x+C$.
Ta có $\int{f\left( x \right)\text{d}x}=\int{\left( 3{{x}^{2}}+8\sin x \right)\text{d}x=} {{x}^{3}}-8\cos x+C$
Đáp án C.