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Câu hỏi: Tìm $F\left( x \right)=\int{{{x}^{100}}\text{d}x}$
A. $F\left( x \right)=\dfrac{{{x}^{100}}}{100}+C.$
B. $F\left( x \right)=\dfrac{{{x}^{101}}}{102}+C.$
C. $F\left( x \right)=\dfrac{{{x}^{101}}}{101}+C.$
D. $F\left( x \right)=\dfrac{{{x}^{99}}}{99}+C.$
A. $F\left( x \right)=\dfrac{{{x}^{100}}}{100}+C.$
B. $F\left( x \right)=\dfrac{{{x}^{101}}}{102}+C.$
C. $F\left( x \right)=\dfrac{{{x}^{101}}}{101}+C.$
D. $F\left( x \right)=\dfrac{{{x}^{99}}}{99}+C.$
Ta có $F\left( x \right)=\int{{{x}^{100}}\text{d}x}=\dfrac{{{x}^{101}}}{101}+C$.
Đáp án C.