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Câu hỏi: Rút gọn biểu thức $P={{x}^{\dfrac{1}{5}}}.\sqrt[3]{x}$ với $x>0.$
A. $P={{x}^{\dfrac{16}{15}}}$.
B. $P={{x}^{\dfrac{3}{5}}}$.
C. $P={{x}^{\dfrac{8}{15}}}$.
D. $P={{x}^{\dfrac{1}{15}}}$.
A. $P={{x}^{\dfrac{16}{15}}}$.
B. $P={{x}^{\dfrac{3}{5}}}$.
C. $P={{x}^{\dfrac{8}{15}}}$.
D. $P={{x}^{\dfrac{1}{15}}}$.
$P={{x}^{\dfrac{1}{5}}}.\sqrt[3]{x}={{x}^{\dfrac{1}{5}}}.{{x}^{\dfrac{1}{3}}}={{x}^{\dfrac{1}{5}+\dfrac{1}{3}}}={{x}^{\dfrac{8}{15}}}$.
Đáp án C.