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Câu hỏi: Nếu $\int\limits_{-2}^{2}{(-3f}(x)+{{x}^{3}}-3x-5)\text{d}x=5$ thì $\int\limits_{-2}^{2}{(-3f}(x)+4{{x}^{3}}-6x-6)\text{d}x$ bằng
A. 1.
B. 0.
C. 3
D. 2.
A. 1.
B. 0.
C. 3
D. 2.
$\begin{aligned}
& \int\limits_{-2}^{2}{(-3f}(x)+4{{x}^{3}}-6x-6)\text{d}x=\int\limits_{-2}^{2}{(-3f}(x)+{{x}^{3}}-3x-5)\text{d}x+\int\limits_{-2}^{2}{(}{{x}^{3}}-3x-1)\text{d}x \\
& =5+(\dfrac{1}{4}x{}^{4}-\dfrac{3}{2}{{x}^{2}}-x)|_{-2}^{2}=5-4=1 \\
\end{aligned}$
& \int\limits_{-2}^{2}{(-3f}(x)+4{{x}^{3}}-6x-6)\text{d}x=\int\limits_{-2}^{2}{(-3f}(x)+{{x}^{3}}-3x-5)\text{d}x+\int\limits_{-2}^{2}{(}{{x}^{3}}-3x-1)\text{d}x \\
& =5+(\dfrac{1}{4}x{}^{4}-\dfrac{3}{2}{{x}^{2}}-x)|_{-2}^{2}=5-4=1 \\
\end{aligned}$
Đáp án A.