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Câu hỏi: Nếu ${\int\limits_{1}^{2022}{f\left( x \right)d\text{x}}=3}$ và ${\int\limits_{1}^{2022}{g\left( x \right)d\text{x}}=4}$ thì ${\int\limits_{1}^{2022}{\left( 2f\left( x \right)-g\left( x \right)+1 \right)d\text{x}}}$ bằng
A. $2023$.
B. $2022$.
C. $2021$.
D. $2022$.
A. $2023$.
B. $2022$.
C. $2021$.
D. $2022$.
Ta có $\int\limits_{1}^{2022}{\left( 2f\left( x \right)-g\left( x \right)+1 \right)d\text{x}}=2\int\limits_{1}^{2022}{f\left( x \right)d\text{x}}-\int\limits_{1}^{2022}{g\left( x \right)d\text{x}}+\int\limits_{1}^{2022}{1d\text{x}}=2.3-4+2021=2023.$.
Đáp án A.