Google
Câu hỏi: Nếu $\int\limits_{1}^{2}{f\left( x \right)}\text{d}x=-2021$ và $\int\limits_{1}^{2}{g\left( x \right)}\text{d}x=2022$ thì $\int\limits_{1}^{2}{\left[ f\left( x \right)+g\left( x \right) \right]}\text{d}x$ bằng
A. $-1$
B. $2022$
C. $1$
D. $4043$
A. $-1$
B. $2022$
C. $1$
D. $4043$
Ta có $\int\limits_{1}^{2}{\left[ f\left( x \right)+g\left( x \right) \right]}\text{d}x=\int\limits_{1}^{2}{f\left( x \right)}\text{d}x+\int\limits_{1}^{2}{g\left( x \right)}\text{d}x=-2021+2022=1$.
Đáp án C.