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Câu hỏi: Nếu $\int\limits_{0}^{1}{f\left( x \right)dx}=2$ và $\int\limits_{0}^{1}{g\left( x \right)dx}=3$ thì $\int\limits_{0}^{1}{\left[ 2020f\left( x \right)-2021g\left( x \right) \right]dx}$ bằng
A. $-2020.$
B. $-1.$
C. $-2023.$
D. $-2021.$
A. $-2020.$
B. $-1.$
C. $-2023.$
D. $-2021.$
Ta có $\int\limits_{0}^{1}{\left[ 2020f\left( x \right)-2021g\left( x \right) \right]dx}=2020\int\limits_{0}^{1}{f\left( x \right)dx}-2021\int\limits_{0}^{1}{g\left( x \right)dx}$
$=2020.2-2021.3=-2023.$
$=2020.2-2021.3=-2023.$
Đáp án C.