Câu hỏi: $\int{\left( {{x}^{2}}-2 \right)\mathrm{d}x}$ bằng A. $\dfrac{1}{3}{{x}^{3}}-2x+C$. B. $3{{x}^{3}}-2x+C$. C. $2x+C$. D. $\dfrac{1}{3}{{x}^{3}}+C$.
Ta có $\int{\left( {{x}^{2}}-2 \right)\mathrm{d}x}=\int{{{x}^{2}}\mathrm{d}x-2\int{\mathrm{d}x=}}\dfrac{1}{3}{{x}^{3}}-2x+C$.
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