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Câu hỏi: Họ nguyên hàm của hàm số $f\left( x \right)=x-2cosx$ là
A. $\int{f\left( x \right)\text{d}}x=x\sin x+2cosx+C.$
B. $\int{f\left( x \right)\text{d}}x=1-2\sin x+C.$
C. $\int{f\left( x \right)\text{d}}x=\dfrac{{{x}^{2}}}{2}-2\sin x+C.$
D. $\int{f\left( x \right)\text{d}}x=\dfrac{{{x}^{2}}}{2}+2\sin x+C.$
A. $\int{f\left( x \right)\text{d}}x=x\sin x+2cosx+C.$
B. $\int{f\left( x \right)\text{d}}x=1-2\sin x+C.$
C. $\int{f\left( x \right)\text{d}}x=\dfrac{{{x}^{2}}}{2}-2\sin x+C.$
D. $\int{f\left( x \right)\text{d}}x=\dfrac{{{x}^{2}}}{2}+2\sin x+C.$
Ta có $\int{f\left( x \right)\text{d}}x=\int{\left( x-2cosx \right)\text{d}}x=\dfrac{{{x}^{2}}}{2}-2\sin x+C.$
Đáp án C.