Câu hỏi: Đặt ${{\log }_{3}}2=a$, khi đó ${{\log }_{3}}\dfrac{4}{27}$ bằng A. $2a-4$. B. $2a-3$. C. $\dfrac{2}{4}\left( a-2 \right)$. D. ${{\left( \dfrac{1}{2}\left( a-2 \right) \right)}^{2}}$.
Ta có: ${{\log }_{3}}\dfrac{4}{27}=$ ${{\log }_{3}}4-{{\log }_{3}}27=2{{\log }_{3}}2-3$ $=2a-3$.