Cường độ dòng điện trong mạch dao động LC có biểu thức $i=9\cos...

${{\text{W}}_{L}}=\dfrac{1}{8}{{\text{W}}_{C}}\left\{ \begin{aligned}
& {{\text{W}}_{L}}=\dfrac{1}{9}\text{W}\Rightarrow \left| i \right|=\sqrt{\dfrac{1}{9}}{{I}_{o}}=3(mA) \\
& {{\text{W}}_{C}}=\dfrac{8}{9}\text{W}. \\
\end{aligned} \right.$
Chú ý: ${{\text{W}}_{C}}=n{{\text{W}}_{L}}\left\{ \begin{aligned}
& {{\text{W}}_{L}}=\dfrac{1}{n+1}\text{W}\Rightarrow \left| i \right|=\sqrt{\dfrac{1}{n+1}}{{I}_{o}} \\
& {{\text{W}}_{C}}=\dfrac{n}{n+1}\text{W}\Rightarrow \left| q \right|=\sqrt{\dfrac{n}{n+1}}{{Q}_{o}};\left| u \right|=\sqrt{\dfrac{n}{n+1}}{{U}_{o}} \\
\end{aligned} \right.$
(Toàn bộ n + 1) phần ${{\text{W}}_{L}}$ chiếm m phần và ${{\text{W}}_{C}}$ chiếm n phần)
$\left\{ \begin{aligned}
& {{\text{W}}_{L}}={{\text{W}}_{C}}\Rightarrow \left| i \right|=\dfrac{{{I}_{o}}}{\sqrt{2}};\left| q \right|=\dfrac{{{Q}_{o}}}{\sqrt{2}};\left| u \right|=\dfrac{{{U}_{o}}}{\sqrt{2}} \\
& {{\text{W}}_{L}}=3{{\text{W}}_{C}}\Rightarrow \left| i \right|=\dfrac{{{I}_{o}}\sqrt{3}}{\sqrt{2}};\left| q \right|=\dfrac{{{Q}_{o}}}{\sqrt{2}};\left| u \right|=\dfrac{{{U}_{o}}}{\sqrt{2}} \\
& {{\text{W}}_{L}}=\dfrac{1}{3}{{\text{W}}_{C}}\Rightarrow \left| i \right|=\dfrac{{{I}_{o}}}{\sqrt{2}};\left| q \right|=\dfrac{{{Q}_{o}}\sqrt{3}}{\sqrt{2}};\left| u \right|=\dfrac{{{U}_{o}}}{\sqrt{2}} \\
\end{aligned} \right.$