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Câu hỏi: Cho $\int\limits_{1}^{3}{f(x)dx=\dfrac{2}{3}; }\int\limits_{1}^{3}{g(x)dx=\dfrac{3}{4}. }$ Khi đó $\int\limits_{1}^{3}{\left[ f(x)-g(x) \right]dx}$ có giá trị bằng
A. $\dfrac{1}{2}.$
B. $\dfrac{17}{12}.$
C. $-\dfrac{1}{12}.$
D. $\dfrac{1}{12}.$
A. $\dfrac{1}{2}.$
B. $\dfrac{17}{12}.$
C. $-\dfrac{1}{12}.$
D. $\dfrac{1}{12}.$
$\int\limits_{1}^{3}{\left[ f\left( x \right)-g\left( x \right) \right]dx}=\int\limits_{1}^{3}{f\left( x \right)dx}-\int\limits_{1}^{3}{g\left( x \right)dx}=-\dfrac{1}{12}$.
Đáp án C.