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Câu hỏi: Cho hàm số $f\left( x \right)=\dfrac{1}{{{x}^{2}}-9}$. Khẳng định nào dưới đây đúng?
A. $\int{f\left( x \right)\text{d}x=\dfrac{1}{6}}\ln \dfrac{x+3}{x-3}+C$.
B. $\int{f\left( x \right)\text{d}x=\dfrac{1}{6}}\ln \left| \dfrac{x-3}{x+3} \right|+C$.
C. $\int{f\left( x \right)\text{d}x=\dfrac{1}{6}}\ln \left| \dfrac{x+3}{x-3} \right|+C$.
D. $\int{f\left( x \right)\text{d}x=}\ln \left| \dfrac{x-3}{x+3} \right|+C$.
A. $\int{f\left( x \right)\text{d}x=\dfrac{1}{6}}\ln \dfrac{x+3}{x-3}+C$.
B. $\int{f\left( x \right)\text{d}x=\dfrac{1}{6}}\ln \left| \dfrac{x-3}{x+3} \right|+C$.
C. $\int{f\left( x \right)\text{d}x=\dfrac{1}{6}}\ln \left| \dfrac{x+3}{x-3} \right|+C$.
D. $\int{f\left( x \right)\text{d}x=}\ln \left| \dfrac{x-3}{x+3} \right|+C$.
$\int{\dfrac{1}{{{x}^{2}}-9}\text{d}x=\dfrac{1}{6}}\ln \left| \dfrac{x-3}{x+3} \right|+C$.
Đáp án B.