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Câu hỏi: Cho hàm số $f\left( x \right)=4{{x}^{3}}+2x+1$. Tìm $\int{f\left( x \right)\text{d}x}$.
A. $\int{f\left( x \right)\text{d}x}=12{{x}^{4}}+2{{x}^{2}}+x+C$.
B. $\int{f\left( x \right)\text{d}x}={{x}^{4}}+{{x}^{2}}+x+C$.
C. $\int{f\left( x \right)\text{d}x}=12{{x}^{2}}+2$.
D. $\int{f\left( x \right)\text{d}x}=12{{x}^{2}}+2+C$.
A. $\int{f\left( x \right)\text{d}x}=12{{x}^{4}}+2{{x}^{2}}+x+C$.
B. $\int{f\left( x \right)\text{d}x}={{x}^{4}}+{{x}^{2}}+x+C$.
C. $\int{f\left( x \right)\text{d}x}=12{{x}^{2}}+2$.
D. $\int{f\left( x \right)\text{d}x}=12{{x}^{2}}+2+C$.
Ta có: $\int{f\left( x \right)\text{d}x}=\int{\left( 4{{x}^{3}}+2x+1 \right)\text{d}x}=4\dfrac{{{x}^{4}}}{4}+2\dfrac{{{x}^{2}}}{2}+x+C$ $={{x}^{4}}+{{x}^{2}}+x+C$.
Đáp án B.