Google
Câu hỏi: Cho dung dịch Ba(HCO3)2 lần lượt vào các dung dịch: CuSO4, NaOH, NaHSO4, K2CO3, Ca(OH)2, HNO3, MgCl2, Ca(NO3)2. Số trường hợp có phản ứng xảy ra là
A. 8.
B. 6.
C. 7.
D. 5.
A. 8.
B. 6.
C. 7.
D. 5.
Các trường hợp có phản ứng xảy ra là:
$CuS{{O}_{4}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to Cu{{\left( OH \right)}_{2}}+BaS{{O}_{4}}+2C{{O}_{2}}$
$NaOH+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaC{{O}_{3}}+N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O$
$NaHS{{O}_{4}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaS{{O}_{4}}+N{{a}_{2}}S{{O}_{4}}+C{{O}_{2}}+{{H}_{2}}O$
${{K}_{2}}C{{O}_{3}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaC{{O}_{3}}+KHC{{O}_{3}}$
$Ca{{\left( OH \right)}_{2}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaC{{O}_{3}}+CaC{{O}_{3}}+{{H}_{2}}O$
$HN{{O}_{3}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to Ba{{\left( N{{O}_{3}} \right)}_{2}}+C{{O}_{2}}+{{H}_{2}}O$
$CuS{{O}_{4}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to Cu{{\left( OH \right)}_{2}}+BaS{{O}_{4}}+2C{{O}_{2}}$
$NaOH+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaC{{O}_{3}}+N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O$
$NaHS{{O}_{4}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaS{{O}_{4}}+N{{a}_{2}}S{{O}_{4}}+C{{O}_{2}}+{{H}_{2}}O$
${{K}_{2}}C{{O}_{3}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaC{{O}_{3}}+KHC{{O}_{3}}$
$Ca{{\left( OH \right)}_{2}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaC{{O}_{3}}+CaC{{O}_{3}}+{{H}_{2}}O$
$HN{{O}_{3}}+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to Ba{{\left( N{{O}_{3}} \right)}_{2}}+C{{O}_{2}}+{{H}_{2}}O$
Đáp án B.