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Câu hỏi: Cho biết không xảy ra đột biến nhưng xảy ra hoán vị gen. Theo lý thuyết, phép lai nào đây cho đời con có nhiều loại kiểu gen nhất?
A. $\dfrac{\text{Ab}}{\text{ab}}\times \dfrac{\text{AB}}{\text{aB}}$
B. $\dfrac{Ab}{ab}\times \dfrac{aB}{ab}$
C. $\dfrac{AB}{ab}\times \dfrac{aB}{ab}$
D. $\dfrac{Ab}{ab}\times \dfrac{ab}{ab}$
A. $\dfrac{\text{Ab}}{\text{ab}}\times \dfrac{\text{AB}}{\text{aB}}$
B. $\dfrac{Ab}{ab}\times \dfrac{aB}{ab}$
C. $\dfrac{AB}{ab}\times \dfrac{aB}{ab}$
D. $\dfrac{Ab}{ab}\times \dfrac{ab}{ab}$
$\begin{aligned}
& A.\dfrac{\text{Ab}}{\text{ab}}\times \dfrac{\text{AB}}{\text{aB}}\to 1\dfrac{\text{Ab}}{\text{aB}}:1\dfrac{\text{AB}}{\text{ab}}:1\dfrac{\text{AB}}{\text{Ab}}\cdot 1\dfrac{\text{aB}}{\text{ab}} \\
& B.\dfrac{Ab}{ab}\times \dfrac{aB}{ab}\to 1\dfrac{Ab}{aB}:1\dfrac{Ab}{ab}:1\dfrac{aB}{ab}:1\dfrac{ab}{ab} \\
\end{aligned}$
$\text{ C}\text{. }\dfrac{AB}{ab}\times \dfrac{aB}{ab}\to (AB:Ab:aB:ab)(aB:ab)\to $ 8 loại kiểu gen
$\text{ D}\text{. }\dfrac{\text{Ab}}{\text{aB}}\times \dfrac{\text{ab}}{\text{ab}}\to (\text{AB}:\text{ab}:\text{aB}:\text{Ab})\times \text{ab}\to 4$ loại kiểu gen
& A.\dfrac{\text{Ab}}{\text{ab}}\times \dfrac{\text{AB}}{\text{aB}}\to 1\dfrac{\text{Ab}}{\text{aB}}:1\dfrac{\text{AB}}{\text{ab}}:1\dfrac{\text{AB}}{\text{Ab}}\cdot 1\dfrac{\text{aB}}{\text{ab}} \\
& B.\dfrac{Ab}{ab}\times \dfrac{aB}{ab}\to 1\dfrac{Ab}{aB}:1\dfrac{Ab}{ab}:1\dfrac{aB}{ab}:1\dfrac{ab}{ab} \\
\end{aligned}$
$\text{ C}\text{. }\dfrac{AB}{ab}\times \dfrac{aB}{ab}\to (AB:Ab:aB:ab)(aB:ab)\to $ 8 loại kiểu gen
$\text{ D}\text{. }\dfrac{\text{Ab}}{\text{aB}}\times \dfrac{\text{ab}}{\text{ab}}\to (\text{AB}:\text{ab}:\text{aB}:\text{Ab})\times \text{ab}\to 4$ loại kiểu gen
Đáp án C.