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Câu hỏi: C5H8O2 có bao nhiêu đồng phân cấu tạo este mạch hở?
A. 14.
B. 15.
C. 17.
D. 18
A. 14.
B. 15.
C. 17.
D. 18
Các đồng phân cấu tạo este mạch hở của ${{C}_{5}}{{H}_{8}}{{O}_{2}}:$
$HCOO-C{{H}_{2}}-C{{H}_{2}}-CH=C{{H}_{2}}$
$HCOO-C{{H}_{2}}-CH=CH-C{{H}_{3}}$
$HCOO-CH=CH-C{{H}_{2}}-C{{H}_{3}}$
$HCOO-C{{H}_{2}}-C\left( C{{H}_{3}} \right)=C{{H}_{2}}$
$HCOO-CH=C{{\left( C{{H}_{3}} \right)}_{2}}$
$HCOO-CH\left( C{{H}_{3}} \right)=CH-C{{H}_{3}}$
$HCOO-C\left( C{{H}_{3}} \right)=CH-C{{H}_{3}}$
$HCOO-C\left( {{C}_{2}}{{H}_{5}} \right)=C{{H}_{2}}$
$C{{H}_{3}}-C\text{OO-CH=CH-C}{{\text{H}}_{3}}$
$C{{H}_{3}}-C\text{OO-C}{{\text{H}}_{2}}-CH=C{{H}_{2}}$
$C{{H}_{3}}-COO-C\left( C{{H}_{3}} \right)=C{{H}_{2}}$
$C{{H}_{3}}-C{{H}_{2}}-COO-CH=C{{H}_{2}}$
$C{{H}_{2}}=CH-COO-C{{H}_{2}}-C{{H}_{3}}$
$C{{H}_{2}}=CH-C{{H}_{2}}-COO-C{{H}_{3}}$
$C{{H}_{3}}-CH=CH-COO-C{{H}_{3}}$
$C{{H}_{2}}=C\left( C{{H}_{3}} \right)-COO-C{{H}_{3}}$
$HCOO-C{{H}_{2}}-C{{H}_{2}}-CH=C{{H}_{2}}$
$HCOO-C{{H}_{2}}-CH=CH-C{{H}_{3}}$
$HCOO-CH=CH-C{{H}_{2}}-C{{H}_{3}}$
$HCOO-C{{H}_{2}}-C\left( C{{H}_{3}} \right)=C{{H}_{2}}$
$HCOO-CH=C{{\left( C{{H}_{3}} \right)}_{2}}$
$HCOO-CH\left( C{{H}_{3}} \right)=CH-C{{H}_{3}}$
$HCOO-C\left( C{{H}_{3}} \right)=CH-C{{H}_{3}}$
$HCOO-C\left( {{C}_{2}}{{H}_{5}} \right)=C{{H}_{2}}$
$C{{H}_{3}}-C\text{OO-CH=CH-C}{{\text{H}}_{3}}$
$C{{H}_{3}}-C\text{OO-C}{{\text{H}}_{2}}-CH=C{{H}_{2}}$
$C{{H}_{3}}-COO-C\left( C{{H}_{3}} \right)=C{{H}_{2}}$
$C{{H}_{3}}-C{{H}_{2}}-COO-CH=C{{H}_{2}}$
$C{{H}_{2}}=CH-COO-C{{H}_{2}}-C{{H}_{3}}$
$C{{H}_{2}}=CH-C{{H}_{2}}-COO-C{{H}_{3}}$
$C{{H}_{3}}-CH=CH-COO-C{{H}_{3}}$
$C{{H}_{2}}=C\left( C{{H}_{3}} \right)-COO-C{{H}_{3}}$
Đáp án C.