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Câu hỏi: Tính năng lượng tỏa ra trong các phản ứng sau:
a)\({}_3^7Li + {}_1^1H \to {}_2^4He + {}_2^4He\)
b)\({}_1^2H + {}_2^3He \to {}_1^1H + {}_2^4He\)
c)\({}_3^6Li + {}_1^2H \to {}_2^4He + {}_2^4He\)
d)\({}_3^6Li + {}_1^1H \to {}_2^3He + {}_2^4He\)
a)\({}_3^7Li + {}_1^1H \to {}_2^4He + {}_2^4He\)
b)\({}_1^2H + {}_2^3He \to {}_1^1H + {}_2^4He\)
c)\({}_3^6Li + {}_1^2H \to {}_2^4He + {}_2^4He\)
d)\({}_3^6Li + {}_1^1H \to {}_2^3He + {}_2^4He\)
Phương pháp giải
Sử dụng công thức tính năng lượng: \(Q = ({m_{truoc}} - {m_{sau}}){c^2}\)
Lấy\({m_{_3^7Li}} = 7,0154u;\) \({m_{_3^6Li}} = 6,0145u;\)\({m_{_1^2H}} = 2,0140u;\)\({m_{_1^1H}} = 1,0073u;\)\({m_{_2^3He}} = 3,0025u;\)\({m_{_2^4He}} = 4,0015u; 1u = 931MeV/{c^2}.\)
Lời giải chi tiết
a) \(Q = ({m_{truoc}} - {m_{sau}}){c^2} \\= (7,0154 + 1,0073 - 4,0015.2). 931 \\= 18,34MeV\)
b) \(Q = ({m_{truoc}} - {m_{sau}}){c^2} \\= (2,014 + 3,0025 - 4,0015 - 1,0073). 931 \\= 7,1687MeV\)
c) \(Q = ({m_{truoc}} - {m_{sau}}){c^2}\\ = (6,0145 + 2,014 - 4,0015.2). 931\\ = 23,74MeV\)
d) \(Q = ({m_{truoc}} - {m_{sau}}){c^2} \\= (6,0145 + 1,0073 - 4,0015 - 3,0025). 931\\ = 16,73MeV\)
Sử dụng công thức tính năng lượng: \(Q = ({m_{truoc}} - {m_{sau}}){c^2}\)
Lấy\({m_{_3^7Li}} = 7,0154u;\) \({m_{_3^6Li}} = 6,0145u;\)\({m_{_1^2H}} = 2,0140u;\)\({m_{_1^1H}} = 1,0073u;\)\({m_{_2^3He}} = 3,0025u;\)\({m_{_2^4He}} = 4,0015u; 1u = 931MeV/{c^2}.\)
Lời giải chi tiết
a) \(Q = ({m_{truoc}} - {m_{sau}}){c^2} \\= (7,0154 + 1,0073 - 4,0015.2). 931 \\= 18,34MeV\)
b) \(Q = ({m_{truoc}} - {m_{sau}}){c^2} \\= (2,014 + 3,0025 - 4,0015 - 1,0073). 931 \\= 7,1687MeV\)
c) \(Q = ({m_{truoc}} - {m_{sau}}){c^2}\\ = (6,0145 + 2,014 - 4,0015.2). 931\\ = 23,74MeV\)
d) \(Q = ({m_{truoc}} - {m_{sau}}){c^2} \\= (6,0145 + 1,0073 - 4,0015 - 3,0025). 931\\ = 16,73MeV\)