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Câu hỏi: Cho sơ đồ phản ứng sau:
2X1 + 2H2O → 2X2 + X3 + H2
2X2 + X4 → BaCO3 + Na2CO3 + 2H2O
X4 + 2X5 → BaSO4 + K2SO4 + 2CO2 + 2H2O
Các chất X1, X4, X5 lần lượt là:
A. NaOH, Ba(HCO3)2, KHSO4.
B. BaCl2, Ba(HCO3)2, H2SO4.
C. NaCl, Ba(HCO3)2, KHSO4.
D. NaCl, NaHCO3, H2SO4.
2X1 + 2H2O → 2X2 + X3 + H2
2X2 + X4 → BaCO3 + Na2CO3 + 2H2O
X4 + 2X5 → BaSO4 + K2SO4 + 2CO2 + 2H2O
Các chất X1, X4, X5 lần lượt là:
A. NaOH, Ba(HCO3)2, KHSO4.
B. BaCl2, Ba(HCO3)2, H2SO4.
C. NaCl, Ba(HCO3)2, KHSO4.
D. NaCl, NaHCO3, H2SO4.
$2{{X}_{1}}+2{{H}_{2}}O\to 2{{X}_{2}}+{{X}_{3}}+{{H}_{2}}$
$2NaCl+2{{H}_{2}}O\to 2NaOH+C{{l}_{2}}+{{H}_{2}}$
$2{{X}_{2}}+{{X}_{4}}\to BaC{{O}_{3}}+N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O$
$2NaOH+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaC{{O}_{3}}+N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O$
${{X}_{4}}+2{{X}_{5}}\to BaS{{O}_{4}}+{{K}_{2}}S{{O}_{4}}+2C{{O}_{2}}+2{{H}_{2}}O$
$Ba{{\left( HC{{O}_{3}} \right)}_{2}}+2KHS{{O}_{4}}\to BaS{{O}_{4}}+{{K}_{2}}S{{O}_{4}}+2C{{O}_{2}}+2{{H}_{2}}O$
$\to {{X}_{1}},{{X}_{4}},{{X}_{5}}$ lần lượt là: $NaCl,Ba{{\left( HC{{O}_{3}} \right)}_{2}},KHS{{O}_{4}}$.
$2NaCl+2{{H}_{2}}O\to 2NaOH+C{{l}_{2}}+{{H}_{2}}$
$2{{X}_{2}}+{{X}_{4}}\to BaC{{O}_{3}}+N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O$
$2NaOH+Ba{{\left( HC{{O}_{3}} \right)}_{2}}\to BaC{{O}_{3}}+N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O$
${{X}_{4}}+2{{X}_{5}}\to BaS{{O}_{4}}+{{K}_{2}}S{{O}_{4}}+2C{{O}_{2}}+2{{H}_{2}}O$
$Ba{{\left( HC{{O}_{3}} \right)}_{2}}+2KHS{{O}_{4}}\to BaS{{O}_{4}}+{{K}_{2}}S{{O}_{4}}+2C{{O}_{2}}+2{{H}_{2}}O$
$\to {{X}_{1}},{{X}_{4}},{{X}_{5}}$ lần lượt là: $NaCl,Ba{{\left( HC{{O}_{3}} \right)}_{2}},KHS{{O}_{4}}$.
Đáp án C.
