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Câu hỏi: Hãy phân tích tên các chât sau thành tên phần thế (nếu có) + tên mạch cacbon chính + tên định chức:
\(\mathop {C{H_3} - C{H_2} - C{H_3}}\limits_{propan} \);
\(\mathop {C{H_2} = CH - C{H_3}}\limits_{propen} \);
\(\mathop {HC \equiv C - C{H_3}}\limits_{propin} \);
\(\mathop {C{H_3} - C{H_2} - COOH}\limits_{axitpropanoic} \)
\(\mathop {ClC{H_2} - C{H_2} - C{H_3}}\limits_{1 - clopropan} \);
\(\mathop {BrC{H_2} - C{H_2}Br}\limits_{1,2 - đibrom etan } \);
\(\mathop {C{H_3} - C{H_2} - C{H_2}OH}\limits_{propan - 1 - ol} \); \(\mathop {C{H_3} - CH = CH - C{H_3}}\limits_{but - 2 - en} \)
\(\mathop {C{H_3} - C{H_2} - C{H_3}}\limits_{propan} \);
\(\mathop {C{H_2} = CH - C{H_3}}\limits_{propen} \);
\(\mathop {HC \equiv C - C{H_3}}\limits_{propin} \);
\(\mathop {C{H_3} - C{H_2} - COOH}\limits_{axitpropanoic} \)
\(\mathop {ClC{H_2} - C{H_2} - C{H_3}}\limits_{1 - clopropan} \);
\(\mathop {BrC{H_2} - C{H_2}Br}\limits_{1,2 - đibrom etan } \);
\(\mathop {C{H_3} - C{H_2} - C{H_2}OH}\limits_{propan - 1 - ol} \); \(\mathop {C{H_3} - CH = CH - C{H_3}}\limits_{but - 2 - en} \)
Lời giải chi tiết
