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Câu hỏi: Viết phương trình điện li của các chất sau trong nước: \(MgS{O_4}, HCl{O_3},{H_2}S, Pb{\left( {OH} \right)_2}, LiOH\)
Lời giải chi tiết
Phương trình điện li:
\(MgS{O_4} \to M{g^{2 + }} + SO_4^{2 - }\)
$\begin{array}{l}
Pb{\left( {OH} \right)_2} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} Pb{\left( {OH} \right)^ + } + O{H^ - }\\
Pb{\left( {OH} \right)^ + } \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} P{b^{2 + }} + O{H^ - }\\
{H_2}S \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + H{S^ - }\\
H{S^ - } \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + {S^{2 - }}
\end{array}$
\(HCl{O_3} \to {H^ + } + ClO_3^ - \)
$\begin{array}{l}
{H_2}Pb{O_2} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + HPb{O_2}^ - \\
HPb{O_2}^ - \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + Pb{O_2}^{2 - }
\end{array}$
Phương trình điện li:
\(MgS{O_4} \to M{g^{2 + }} + SO_4^{2 - }\)
$\begin{array}{l}
Pb{\left( {OH} \right)_2} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} Pb{\left( {OH} \right)^ + } + O{H^ - }\\
Pb{\left( {OH} \right)^ + } \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} P{b^{2 + }} + O{H^ - }\\
{H_2}S \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + H{S^ - }\\
H{S^ - } \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + {S^{2 - }}
\end{array}$
\(HCl{O_3} \to {H^ + } + ClO_3^ - \)
$\begin{array}{l}
{H_2}Pb{O_2} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + HPb{O_2}^ - \\
HPb{O_2}^ - \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {H^ + } + Pb{O_2}^{2 - }
\end{array}$